2/1X3/1+3/1x4/1+4/1x5/1+5/1x6/1.41/1X42/1的和

因式分解：x4+x3+2x2 +x+1 线性代数!解非其次线性方程组；【2x1+x2-x3+x4=1；4x1+2x2-2x3+x4=2；2x1+x-x3-x4=1】. 用矩阵法姐方程组：2x1-3x2 +x 3-x4 =3 3x 1+x2 +x3 +x 4=0 4x1 -x2 -x 3-x4 =7 -2x 1-x3 +x3 +x4 =-5 用克拉默法则解下列方程组 x1-2x2+3x3-4x4=4 x2-x3+x4=-3 x1+3x2+2x4=1 -7x2+3x3+x4=3x1-2x2+3x3-4x4=4x2-x3+x4=-3 x1+3x2+2x4=1 -7x2+3x3+x4=3 x5-x4+x3-x2+x-1因式分解 X5-X4+X3+X2+X+1因式分解 x4-x3+x-1 求分解因式? x+x3/1+x4怎么求积分 求出不等式解集1+x-x3-x4>0 x3-2x2+3 1+x+x2+x3+x4=0,那1+x+x2+x3+x4+……+x2004=?注意:2 3 4 2004都表示 方 . x4+x3+2x²+x+1分解因式 x1-x2+x3=1x2-x3+x4=21若x1,x2,x3,x4,x5满足方程组 x3-x4+x5=3x4-x5+x1=4x5-x1+x2=5求x2 x3 x4的值2已知 x1+x4+x6+x7=39 x2+x4+x5+x7=49 x3+x5+x6+x7=41 x4+x7=13 x5+x7=14 x6+x7=9 x1+x2+x3+x4+x5+x6+x7=9求x7的值若x1,x2,x3,x4,x5满足方程组 x1-x (2x4-5x2-4x+1)-(3x3-5x2-3x) X2+X+1=0 X4+2X3+4X2+3X+2=? 已知x2-3x+1=0,求x4-6x3+4x2+15x+2 1x2+2x3+3x4+4x5+.+15x16 1x1!+2x2!+3x3!+4x4!.nxn! 用列主元Gauss消元法解线性方程组{-x2-x3+x4=0,x1-x2+x3-3x4=1,2x1-2x2-4x3+6x4=-1,x1-2x2-4x3+x4=-1