1.2/n(n+1)(n+2)2.n(n+1)(n+2)3.n(n+1)4,∑k3=1^3+2^3+……n^3=
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/12 20:12:09
1.2/n(n+1)(n+2)2.n(n+1)(n+2)3.n(n+1)4,∑k3=1^3+2^3+……n^3=1.2/n(n+1)(n+2)2.n(n+1)(n+2)3.n(n+1)4,∑k3=1^
1.2/n(n+1)(n+2)2.n(n+1)(n+2)3.n(n+1)4,∑k3=1^3+2^3+……n^3=
1.2/n(n+1)(n+2)
2.n(n+1)(n+2)
3.n(n+1)
4,∑k3=1^3+2^3+……n^3=
1.2/n(n+1)(n+2)2.n(n+1)(n+2)3.n(n+1)4,∑k3=1^3+2^3+……n^3=
1、1/(n+1)n-1/(n+1)(n+2)
什么意思?
2^n/n*(n+1)
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
n
n
n
n
(n+2)!/(n+1)!
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n
n^(n+1/n)/(n+1/n)^n
化简(n+1)(n+2)(n+3)
n*【n+1】*【n+2】化简成什么?
2n/(n+1)n!
n(n+1)(n+2)等于多少?
n+(n-1)÷2×n 求化简