lim(3x^3+2x^2cosx+1)/(x^3-2xsinx+3)= 其中x趋向无穷大

x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)是怎么通分的?x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)thank you lim(x_sin)/(3x+2cosx) 求极限lim(x+3)(2+cosx)/(x^2+x) 求极限lim(x->0) 1/x^3 {[(2+cosx)/3]^x-1}求极限lim(x->0)1/x^3 {[(2+cosx)/3]^x-1} 极限lim(2x^2+x)(sinx+cosx)/x^3-2x+1= 请问高手 x趋近于0 lim (sinx-x*cosx)/(sinx)^3 能不能这样计算原式=lim sinx/(sinx)^3-lim (x*cosx)/(sinx)^3=lim 1/(sinx)^2-lim cosx/(sinx)^2=lim (1-cosx)/(sinx)^2=lim (x^2/2)/(x^2)=1/2,如果可以为何与利用麦克劳林公式所得 lim {(cosx)^(1/2)-(cosx)^(1/3)}/ (sinx)^2 x趋近于0 lim {(cosx)^(1/2)-(cosx)^(1/3)}/ (sinx)^2 x趋近于0 1.lim ([x]-|x|)x->1-2.lim (1-cosx)/xx->派/3这道题的答案是3/(2派) 求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0 1.lim x->∞ （2x/x^2+1)*cosx 2..lim x->∞{ [(x^2-x)arctanx]/x^3-x-5}3..lim x->0 （e^x-e^-x-2x)/(x-sinx) 4..lim x->0 (sinx-x)/(x^3) 5..lim x->0 (x^2*tanx)/(x-tanx) 6..lim x->0 (1+3/x)^2x 7..lim x->0 (1+2x)^(3/sinx) 8.lim x->∞ (x/1+x)^(x-3) 9..li lim {[(1+2x)^1/2(1-cosx)]/x^3}=?x→0 lim(x^3+1)(3+cosx)/2x^4-1(x趋向无穷大)的极限 lim x趋于0时：[（2+cosx/3)^x - 1] / x^3 lim[(1/(sinx)^2)-(cosx)^2/x^x] x接近于0答案是4/3 1、lim(x->无穷大) e^x arctanx2、lim(x->0)sinx√1+sin(1/x)3、lim(x->无穷大)【（√x^2+x+1）-【(√x^2-x+1)】4、lim(x->无穷大)((x+{x+(x)^0.5]^0.5}^0.5)/(2x+1)^0.55、lim(x->0)(sin3x+x^2sin1/x)/((1+cosx)x)6、lim(n->无穷大)(2^n)(si 洛必达法则(1)条件?(2)lim(x->0)P(x)/Q(x)=?已知:lim(x->0)P(x)=A(x),lim(x->0)Q(x)=B(x)可不可以:lim(x->0)P(x)/Q(x)=lim(x->0)A(x)/B(x)(3)lim(x->0)[(1+x)^(1/x)-e]/(cosx-1)=? lim [(x^2+1)/(x^3+1)] *(3+cosx) (n→∞)