1/2+1/2+3/8+...+n/2n次方=

来源：学生作业帮助网编辑：六六作业网时间：2025/01/03 15:35:05

1/2+1/2+3/8+...+n/2n次方=1/2+1/2+3/8+...+n/2n次方=1/2+1/2+3/8+...+n/2n次方=设S=1/2+2/4+3/8+……+n/2^n1/2*S=1/

1/2+1/2+3/8+...+n/2n次方=
1/2+1/2+3/8+...+n/2n次方=

1/2+1/2+3/8+...+n/2n次方=
设 S=1/2+2/4+3/8+……+n/2^n
1/2*S=1/4+2/8+……+(n-1)/2^n+n/2^(n+1)
两式想减得：
1/2*S=1/2+1/4+1/8+……+1/2^n-n/2^(n+1)
=1/2*(1-(1/2)^n)÷ (1-1/2)-n/2^(n+1)
=1-1/2^n-n/2^(n+1)
∴ S=2-1/2^(n-1)-n/2^n
手机提问的朋友在客户端右上角评价点【满意】即可.
互相帮助,祝共同进步!

证明不等式：(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n 2^n/n*(n+1) [3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简 [3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简化简n分之n-1+n分之n-2+n分之n-3+.+n分之1 化简n分之n-1+n分之n-2+n分之n-3+.+n分之1 化简(n+1)(n+2)(n+3) 当n为正偶数,求证n/(n-1)+n(n-2)/(n-1)(n-3)+...+n(n-2).2/(n-1)(n-3)...1=n 3(n-1)(n+3)-2(n-5)(n-2) lim2^n +3^n/2^n+1+3^n+1 n(n+1)(n+2)(n+3)+1 因式分解 n(n+1)(n+2)(n+3)+1等于多少 lim(n+3)(4-n)/(n-1)(3-2n) lim(n^3+n)/(n^4-3n^2+1) lim[(n+3)/(n+1))]^(n-2) 【n无穷大】 lim(2^n+3^n)^1 (n趋向无穷) 级数n/(n+1)(n+2)(n+3)和是多少 n*1+n*2+n*3+n*4.求公式