级数n/(n+1)(n+2)(n+3)和是多少

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级数n/(n+1)(n+2)(n+3)和是多少级数n/(n+1)(n+2)(n+3)和是多少级数n/(n+1)(n+2)(n+3)和是多少n/(n+1)(n+2)(n+3)=(n+1-1)/(n+1)

级数n/(n+1)(n+2)(n+3)和是多少
级数n/(n+1)(n+2)(n+3)和是多少

级数n/(n+1)(n+2)(n+3)和是多少
n/(n+1)(n+2)(n+3)=(n+1-1)/(n+1)(n+2)(n+3)=1/(n+2)(n+3)-1/(n+1)(n+2)(n+3)=[1/(n+2)-1/(n+3)]-(1/2)[1/(n+1)(n+2)-1/(n+2)(n+3)],求和得到1/3-(1/2)*(1/(2*3))=1/4.

n/(n+1)(n+2)(n+3)=[3(n+1)-(n+3)]/2(n+1)(n+2)(n+3)
=3/2(n+2)(n+3)-1/2(n+2)(n+3)
所以级数和为(3/2)(1/(1+2))-(1/2)(1/(1+1))=1/4

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