若数列{an}满足a1=根号6 a(n+1)=根号下an+6 (n∈N*) 如果lim an 存在,求lim an的值[数列极限]

若数列{an}满足a1=根号6 a(n+1)=根号下an+6 (n∈N*) 如果lim an 存在,求lim an的值[数列极限] 若数列an满足a1=√6,a(n+1)=√(an+6),如果lim（an）存在,求lim（an）n趋向于无穷,n属于N*,√是根号的意思谢谢 通项公式为an=a（n^2)+n的数列{an},若满足a1 已知数列{an}满足an>0,a1=3 根号下[a(n+1)]=(根号下an)+1 （n属于N*) 则an=?如题. 已知数列满足a1=1,根号a（n-1）-根号an=根号an*a（n-1）,求an 已知数列{an}满足a1=0 a(n+1)=(an-根号3）/(根号3an+1) (n属于N*）,则a20=? 已知数列{an}满足an^2=a(n+1)an-1(n>=1),且a1=根号2,则与根号(a2005)最接近的自然数是 已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an数列{an}满足:an>0,且根号下Sn=an+1/4,求通项an 已知数列{an}满足a1=2,根号下a(n+1)/2an等于n+1/n,求{an}的通项公式? 已知数列{an}满足a1=5,a(n+1)=an+6n+6,则an= 已知数列{an}满足a(n+1)=an+n,a1=1,则an= 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 一道高三数列题,急已知数列{an},满足a1=a+2(a大于等于0)an+1=根号下(an+a)/2,n属于N* (1)若a=0求{an}通项公式 (2)设bn=|an+1-an|数列{bn}的前n项和Sn,证明Sn大于a1 已知数列{an}满足A1=0,A(N+1)=AN减去根号三/根号三AN加1.求A2,A3,A4,A5,A6N为正整数 已知数列{an}满足A1=0,A(N+1)=AN减去根号三/根号三AN加1.求通项公式和A20 若数列an满足a1=1,an+1=2^nan...若数列an满足a1=1,a（n+1）=2^n·an,则数列an的通项公式? 数列{An}满足A1=5,A2=5,A(n+1)=An+6A(n-1)(n≥2,n∈N*).若数列{A(n+1)+kAn}是等比数列已知数列{An}满足A1=5,A2=5,A(n+1)=An+6A(n-1)(n大于等于2,n属于整整数)若数列{A(n+1)+kAn}是等比数列.(1)求数列{An}的通项公式 (2) 已知数列{An}满足A1=1,A(n+1)=6A(n)+1,求{An}通项公式