计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log259)
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计算(log43+log83)(log32+log92)--log1/232^(1/3)+5^(log259)计算(log43+log83)(log32+log92)--log1/232^(1/3)+
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log259)
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log259)
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log259)
答案是71/12,请给分,
计算log9(根号2)*[log4(3)+log8(3)]
计算:(log4 3+log8 3)×log9 √2=?
log4(3)+log8(3) 怎么算
log4(3)+log8(3) 怎么相加?
(log4(3)+log8(3))*log3(2)
计算(log2 3+log4 9+log8 27+……+log2^n 3^n)log9 n次根号3计算(log2 3+log4 9+log8 27+……+log2^n 3^n)log9 n次根号32
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log259)
(log4^3+log8^3)(log3^2+log9^2)详细计算过程.~
计算:1 (log4 3+log8 3)log3 2 2 loga b×logb c×logc a
急 求 (log3 2+log9 2)-(log4 3+log8 3)求 (log3 2+log9 2)-(log4 3+log8 3)
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的?
【(log4)^3+.(log8)^3】【.(log3)^2+.(log9)^2】=几啊
化简此式(log4 3+log8 3)×(log3 2+log9 2)
(log3^2 + log9^4)×(log4^3 + log8^3)
(log3 2+log9 2)*(log4 3+log8 3)求值
化简(log4(3)+log8(3))(log3(2)+log9(2))
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?..