若3x-5y+4z=17,2x+10y+z=13,则x+y+z=
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/24 07:48:15
若3x-5y+4z=17,2x+10y+z=13,则x+y+z=若3x-5y+4z=17,2x+10y+z=13,则x+y+z=若3x-5y+4z=17,2x+10y+z=13,则x+y+z=3x-5
若3x-5y+4z=17,2x+10y+z=13,则x+y+z=
若3x-5y+4z=17,2x+10y+z=13,则x+y+z=
若3x-5y+4z=17,2x+10y+z=13,则x+y+z=
3x-5y+4z=17,2x+10y+z=13
两式相加得:5x+5y+5z=30
则:x+y+z=6
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
若3x-5y+4z=17,2x+10y+z=13,则x+y+z=
若3x+7y+z=5,4x+10y+z=3,则x+y+z=?
若x/2=y/3=z/4,则3x-2y+5z/x+y+z=
x+y+2z=5 2x-y-z=4 3x+y-3z=10
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
-2X+3Y+Z=-4-X-5Y-2Z=-13X+Y-Z=10
若x/3=y/4=z/5,求x+y+z/3x-2y+z的值.
三元一次方程组,1.x-2y+z=9 2x+y+3z=10 3x+2y1.x-2y+z=92x+y+3z=103x+2y-z2.3x-5y+2z=14x+5y-z=5X-5y+3z=-23.7x+2y-z=76x-y+z=74x+3y+z=94.4x+3y-2z=-75x-6y+z=12x+z=-25.2x+3y-4z=-23x-2y+5z=262x+5z=31
方程组{x/2+y/3-z=-5,x/3-y/2+z/2=10,x/2-y/3-z/4=6,求x,y,z
x+y-2z=5 2x-y-z=4 3x+y-3z=10;分别求x、y、z的值.
已知4x-3y-6z=0,x+2y-7z=0,求5x+2y-z/2x-3y-10z
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
2x+z=10 x+y-z=4 3x-y-z=0
若x/2=y/3=z/4则3x-2y+5z/x+y+x=