lim[(1-cosx)^1/2]/sinx,x趋于0,求极限

证明当x→0时,[√(1+xsinx)-√(cosx)]～(3/4)x^2.当x→0时,[√(1+xsinx)-√(cosx)]～(3/4)x^2 lim[√(1+xsinx)-√(cosx)]/[(3/4)x^2] =lim(1+xsinx-cosx)/{[√(1+xsinx)+√(cosx)][(3/4)x^2]} =(2/3)lim(1+xsinx-cosx)/(x^2) =(2/3)lim(sinx+xcosx+si 1、lim(x->无穷大) e^x arctanx2、lim(x->0)sinx√1+sin(1/x)3、lim(x->无穷大)【（√x^2+x+1）-【(√x^2-x+1)】4、lim(x->无穷大)((x+{x+(x)^0.5]^0.5}^0.5)/(2x+1)^0.55、lim(x->0)(sin3x+x^2sin1/x)/((1+cosx)x)6、lim(n->无穷大)(2^n)(si 求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0 lim(tan5x-cosx+1)/sin3x lim(x→0)(cosx)^(1/ln(1+x^2)) lim (cosx)^ln(1/1+x^2)怎么算 lim(x趋向0+)x/[(1-cosx)^(1/2)] lim x->0 cos(2x)-1 / cosx -1 = lim(x→0)[(secx)^2-1] /(1-cosx) lim((sqr(2)-sqr(1+cosx))/((sinx)^2)) x->0 lim（x趋向于0）（1-cosx)/x^2 求极限lim (e^x^2)/cosx-1 区域0 极限lim(x趋进0)(1-cosx)^2secx lim(x->0)[cosx^(1/2)]^(π/x) lim x→0(1+2cosx)^secx x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)是怎么通分的?x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)thank you 求极限 lim x->0 1-cosx / 2x^2lim x->0 1-cosx / 2x^2 (1) lim(x->正无穷) x-lnx (2) lim(x->0+) cosx^1/x^2