x+2y-3z=10 3x+2y=10 6y+2z=-1解三元一次

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x+2y-3z=103x+2y=106y+2z=-1解三元一次x+2y-3z=103x+2y=106y+2z=-1解三元一次x+2y-3z=103x+2y=106y+2z=-1解三元一次1式乘以3得：

x+2y-3z=10 3x+2y=10 6y+2z=-1解三元一次
x+2y-3z=10 3x+2y=10 6y+2z=-1
解三元一次

x+2y-3z=10 3x+2y=10 6y+2z=-1解三元一次
1式乘以3得：3x+6y-9z=30
然后减去2式得4y-9z=20(4)
把3式转化为：y=-(1+2z)/6代入4式
得-2/3（1+2z)-9z=20 解得z= - 2
将z=-2代入3式得y=1/2
将y=1/2代入2式得x=3

把x,z用y表示，由1式可得y=0.5，带入2,3式，得x=3，z=-2

(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian X=3z X+y+z=12 X+2y-2z=10 2x+z=10 x+y-z=4 3x-y-z=0 3X+2y+z=20 x+y+z=10 Y=3X {2x+y=10 {x-y+z=4 {3x-y-z=0 (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 10X+Y+1/3Z=10Y+X 10X+Y+2/3Z=100X+Y 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z x+2y+3z=23 y-z=5 x+2z=10 x+y/2=2y-z/3=2 x-3y+z=10 x+2y+3z=10,x-y+4z=10,x+3y+2z=2 x+2y+3z=10,x-y+4z=10,x+3y+2z=2 解方程：｛3x-y-z=2,｛3y-x-z=-10,｛3z-x-y=10 {x+2y+3z=11,x-y+7z=10,x+3y+2z=2 x-y+4z=10,x+3y+2z=2,x+2y+3z=11.