lim(e^x-cosx)/xsinx x趋向0

lim e-e^cosx除以xsinx x趋向0 lim(e^x-cosx)/xsinx x趋向0 lim(x→-∞）e^xsinx lim(e^-xsinx)x趋于+无穷大 求下列极限lim(x→0)(1-cosx)/xsinx lim(x→0)(1-cosx)/(xsinx)=? 1-√cosx/xsinx 求Lim X趋向于0 lim(x趋向于0)(cosx)^[1/(xsinx)]= x-0 lim(e^x-e^-4)/xsinx lim(e^2-x)/xsinx x→0 怎么求? 高数,y=e^x(cosx+xsinx)的导数, 证明当x→0时,[√(1+xsinx)-√(cosx)]～(3/4)x^2.当x→0时,[√(1+xsinx)-√(cosx)]～(3/4)x^2 lim[√(1+xsinx)-√(cosx)]/[(3/4)x^2] =lim(1+xsinx-cosx)/{[√(1+xsinx)+√(cosx)][(3/4)x^2]} =(2/3)lim(1+xsinx-cosx)/(x^2) =(2/3)lim(sinx+xcosx+si .证明当x→0时,[√(1+xsinx)-√(cosx)]～(3/4)x^2.当x→0时,[√(1+xsinx)-√(cosx)]～(3/4)x^2 lim[√(1+xsinx)-√(cosx)]/[(3/4)x^2] =lim(1+xsinx-cosx)/{[√(1+xsinx)+√(cosx)][(3/4)x^2]} =(2/3)lim(1+xsinx-cosx)/(x^2) =(2/3)lim(sinx+xcosx+s 求极限x→0时,lim[√(1+xsinx)–cosx]/x² 求极限~lim(x→0)[(1+xsinx)^1/2-cosx]/sin^2(x/2) 求,x趋近于0时,lim[根号下(1+xsinx)-cosx]/x的平方= lim x→0 (1-cosx)ln(1+x^2)/xsinx^3 lim(x->0)x^2/[(1+xsinx)^1/2-(cosx)^1/2]是多少?