已知cosx+cos(x+π/3)=Acos(x+φ),设A>0,φ∈(-π/2,π/2)则A=____,φ=____.

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已知cosx+cos(x+π/3)=Acos(x+φ),设A>0,φ∈(-π/2,π/2)则A=____,φ=____.已知cosx+cos(x+π/3)=Acos(x+φ),设A>0,φ∈(-π/2

已知cosx+cos(x+π/3)=Acos(x+φ),设A>0,φ∈(-π/2,π/2)则A=____,φ=____.
已知cosx+cos(x+π/3)=Acos(x+φ),设A>0,φ∈(-π/2,π/2)则A=____,φ=____.

已知cosx+cos(x+π/3)=Acos(x+φ),设A>0,φ∈(-π/2,π/2)则A=____,φ=____.
cosx+cos(x+π/3)
=cos(x+π/6-π/6)+cos(x+π/6+π/6)
=cos(x+π/6)cosπ/6+sin(x+π/6)sinπ/6+cos(x+π/6)cosπ/6-sin(x+π/6)sinπ/6
=2cos(x+π/6)cosπ/6
=(根号3)cos(x+π/6)
所以A=根号3,φ=π/6