求方程1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+1994)(x+1995)的解

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求方程1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+1994)(x+1995)的解求方程1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+1994)(x+1

求方程1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+1994)(x+1995)的解
求方程1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+1994)(x+1995)的解

求方程1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+1994)(x+1995)的解
等号在哪啊?这是方程么?
如果要是这一长串式子化简的话,解法如下:
首先:给你个公式1/a*(a+1)=1/a-1/(a+1)
因此1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+1994)(x+1995)=
1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+...+1/(x+1994)-1/(x+1995)=
1/(x+1)-1/(x+1995)(中间的一减一加都约掉了)=1994/(x+1)*(x+1995)(通分了)
如果要有方程的话,看看你后面是等于什么,应该可以自己解决了吧