sinxcosx=2/5,且根号下cosx^2=-cosx,求,tanx+1/tanx=?

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sinxcosx=2/5,且根号下cosx^2=-cosx,求,tanx+1/tanx=?sinxcosx=2/5,且根号下cosx^2=-cosx,求,tanx+1/tanx=?sinxcosx=2

sinxcosx=2/5,且根号下cosx^2=-cosx,求,tanx+1/tanx=?
sinxcosx=2/5,且根号下cosx^2=-cosx,求,tanx+1/tanx=?

sinxcosx=2/5,且根号下cosx^2=-cosx,求,tanx+1/tanx=?
原式=sinx/cosx+cosx/sinx
=(sin²x+cos²x)/sinxcosx
=1/(2/5)
=5/2