1+1/2-1/(n+1)-1/(n+2)=?怎么算?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/16 17:53:48
1+1/2-1/(n+1)-1/(n+2)=?怎么算?1+1/2-1/(n+1)-1/(n+2)=?怎么算?1+1/2-1/(n+1)-1/(n+2)=?怎么算?1+1/2-1/(n+1)-1/(n+
1+1/2-1/(n+1)-1/(n+2)=?怎么算?
1+1/2-1/(n+1)-1/(n+2)=?怎么算?
1+1/2-1/(n+1)-1/(n+2)=?怎么算?
1+1/2-1/(n+1)-1/(n+2)
=3/2-(2n+3)/(n+1)(n+2)
=【3(n+1)(n+2)-2(2n+3)】/2(n+1)(n+2)
=n(3n+2)//2(n+1)(n+2)
2^n/n*(n+1)
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
2n/(n+1)n!
(n+2)!/(n+1)!
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n
化简(n+1)(n+2)(n+3)
n*【n+1】*【n+2】化简成什么?
n(n+1)(n+2)等于多少?
n+(n-1)÷2×n 求化简
n(n+1)(n+2)什么意思
1^n+2^n+...+2013^n
当n为正偶数,求证n/(n-1)+n(n-2)/(n-1)(n-3)+...+n(n-2).2/(n-1)(n-3)...1=n
1*N+2*(N-1)+3*(N-2)+...+N*1=1/6N(N+1)(N+2)
求极限,N趋向无穷,n^2 ((a+1/n)^(1/n)-a^(1/n))n^2 *((a+1/n)^(1/n)-a^(1/n))