1+1/2-1/(n+1)-1/(n+2)=?怎么算?

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1+1/2-1/(n+1)-1/(n+2)=?怎么算?1+1/2-1/(n+1)-1/(n+2)=?怎么算?1+1/2-1/(n+1)-1/(n+2)=?怎么算?1+1/2-1/(n+1)-1/(n+

1+1/2-1/(n+1)-1/(n+2)=?怎么算?
1+1/2-1/(n+1)-1/(n+2)=?怎么算?

1+1/2-1/(n+1)-1/(n+2)=?怎么算?
1+1/2-1/(n+1)-1/(n+2)
=3/2-(2n+3)/(n+1)(n+2)
=【3(n+1)(n+2)-2(2n+3)】/2(n+1)(n+2)
=n(3n+2)//2(n+1)(n+2)