Find out F(1)=?If dy/dx =1/2x,and f(e)=0
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FindoutF(1)=?Ifdy/dx=1/2x,andf(e)=0FindoutF(1)=?Ifdy/dx=1/2x,andf(e)=0FindoutF(1)=?Ifdy/dx=1/2x,andf
Find out F(1)=?If dy/dx =1/2x,and f(e)=0
Find out F(1)=?If dy/dx =1/2x,and f(e)=0
Find out F(1)=?If dy/dx =1/2x,and f(e)=0
dy/dx = 1/(2x)
y = (1/2)lnx + C
y(e) = 1/2+ C = 0
C= -1/2
y = (1/2)(lnx -1)
y(1) = -1/2
一楼的回答的是真确的
因为dy/dx =1/2x，所以求得F(X)=X^2+C,又 f(e)=0，所以C=-e^2,既F(X)=X^2-e^2.所以F(1)=1-e^2
Find out F(1)=?If dy/dx =1/2x,and f(e)=0
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