(a-1)^2n-1 +2(1-a)^2n+(a-1)^2n+1因式分解
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(a-1)^2n-1+2(1-a)^2n+(a-1)^2n+1因式分解(a-1)^2n-1+2(1-a)^2n+(a-1)^2n+1因式分解(a-1)^2n-1+2(1-a)^2n+(a-1)^2n+
(a-1)^2n-1 +2(1-a)^2n+(a-1)^2n+1因式分解
(a-1)^2n-1 +2(1-a)^2n+(a-1)^2n+1因式分解
(a-1)^2n-1 +2(1-a)^2n+(a-1)^2n+1因式分解
原式=(a-1)^(2n-1)+2(1-a)^2n+(a-1)^(2n+1)
=(a-1)^(2n-1)+2(a-1)^2n+(a-1)^(2n+1)
=(a-1)^(2n-1)[1+2(a-1)+(a-1)^2]
=(a-1)^(2n-1)(1+a-1)^2
=(a-1)^(2n-1)a^2
设a,n∈N*证明a^2n-(-a)^n≥(a+1)×a^n
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