lim(x趋向无穷)((3-2x)/(2-2x))^x
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/28 03:46:20
lim(x趋向无穷)((3-2x)/(2-2x))^xlim(x趋向无穷)((3-2x)/(2-2x))^xlim(x趋向无穷)((3-2x)/(2-2x))^x(3-2x)/(2-2x)=1+1/(
lim(x趋向无穷)((3-2x)/(2-2x))^x
lim(x趋向无穷)((3-2x)/(2-2x))^x
lim(x趋向无穷)((3-2x)/(2-2x))^x
(3-2x)/(2-2x)=1+1/(2-2x)
令t=1/(2-2x),则x=1-(1/2t)则x→无穷时,t→0
lim(x趋向无穷)((3-2x)/(2-2x))^x
=lim(t→0)(1+t)^[1-(1/2t)]
=lim(t→0)(1+t)/√[(1+t)^1/t]
=1/√e
=e^-1/2
极限要多做题的
(3-2x)/(2-2x)=1+1/(2-2x)
令t=1/(2-2x),则x=1-(1/2t)则x→无穷时,t→0
lim(x趋向无穷)((3-2x)/(2-2x))^x
=lim(t→0)(1+t)^[1-(1/2t)]
=lim(t→0)(1+t)/√[(1+t)^1/t]
=1/√e
=e^-1/2
lim(x趋向无穷)(cos1/根号x)^2x
lim(x趋向无穷)((3-2x)/(2-2x))^x
lim(x趋向无穷)[1-(2/x)]^3x
lim(((x^2)/(1+x^2))^x)x趋向于无穷求大神详解
当x趋向于正无穷,求lim{{(x+1)^2*(3x-1)^3}/x^4*(x+4)}
求下列式子的值(1)lim(x趋向无穷) (2x+7)/[(x-1)(x+2)]=?(2)lim(x趋向无穷) (3x^2+2x+1)/[(3x+1)(3x-1)]=?
大学高数求大神lim(x趋向无穷)[(x-2)^3*(3x-1)^2]/(x^5+1)不用过程
lim[ln(2^x+3^x)^(1/x)](x趋向于无穷) 结果是什么我可以求出来,
高数极限lim(x趋向无穷)x/根号(x^2+1)=?
求lim(x趋向于无穷)(1-1/x^2)^x的极限
lim〈x趋向无穷〉 ln(1+2x)/x
lim x趋向于无穷 {1+[2/(1+x)]}^x
x趋向无穷时Lim(x+1)/(2x+1)=
求极限lim(x趋向于正无穷)ln(2x)/ln(x)
求极限lim x趋向无穷 根号(x^2+x)下 - xlim x趋向正无穷 根号(x^2+x)下 - x
lim(n趋向无穷)=[(5x^2+1)/(3x-1)]sin1/x=?
lim (n趋向无穷)(x/1+x)x次方
lim(x趋向无穷)-(x+1)+√(x^2+1)