证明1+1/(√2)+1/(√3)+……+1/(√n)

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证明1+1/(√2)+1/(√3)+……+1/(√n)证明1+1/(√2)+1/(√3)+……+1/(√n)证明1+1/(√2)+1/(√3)+……+1/(√n)证明:因为1/(√n)=所以1/(√2

证明1+1/(√2)+1/(√3)+……+1/(√n)
证明1+1/(√2)+1/(√3)+……+1/(√n)

证明1+1/(√2)+1/(√3)+……+1/(√n)
证明:因为 1/(√n)=<2/[√n+(√(n-1)]=2[√n-(√(n-1)]
所以
1/(√2)<2/(√2-1)
1/(√3)<2/(√3-√2)
1/(√4)<2/(√4-√3)
……………………
1/(√n)<2/(√n-√n-1)
相加得1/(√2)+1/(√3)+……+1/(√n)<2√n -2
所以1+1/(√2)+1/(√3)+……+1/(√n)<2√n -1<2√n
证毕!

n=k
n=k+1
那套东西做..
证明题蒸出来就行了

只能用数归了,你卡在那里?