求不定积分∫x^2/(1-x^4)dx

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求不定积分∫x^2/(1-x^4)dx求不定积分∫x^2/(1-x^4)dx求不定积分∫x^2/(1-x^4)dx∫x^2/(1-x^4)dx=∫x^2/[(1-x^2)(1+x^2)]dx=1/2·

求不定积分∫x^2/(1-x^4)dx
求不定积分∫x^2/(1-x^4)dx

求不定积分∫x^2/(1-x^4)dx
∫x^2/(1-x^4)dx
=∫x^2/[(1-x^2)(1+x^2)]dx
=1/2·∫1/(1-x^2)dx-1/2·∫1/(1+x^2)dx
=1/4·∫1/(1-x)dx+1/4·∫1/(1+x)dx-1/2·∫1/(1+x^2)dx
= -1/4·ln|1-x|+1/4·ln|1+x|-1/2·arctanx+C