已知cosa=-5/13,a∈(π/2,π),则sin(a-π/3)=

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已知cosa=-5/13,a∈(π/2,π),则sin(a-π/3)=已知cosa=-5/13,a∈(π/2,π),则sin(a-π/3)=已知cosa=-5/13,a∈(π/2,π),则sin(a-

已知cosa=-5/13,a∈(π/2,π),则sin(a-π/3)=
已知cosa=-5/13,a∈(π/2,π),则sin(a-π/3)=

已知cosa=-5/13,a∈(π/2,π),则sin(a-π/3)=
sina=√(1-cos²a)=12/13
sin(a-π/3)=sinacosπ/3-cosasinπ/3
=12/13×1/2-(-5/13)×√3/2
=6/13+5√3/26