已知y=ln(x+e^x^2) 求dy/dx

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已知y=ln(x+e^x^2)求dy/dx已知y=ln(x+e^x^2)求dy/dx已知y=ln(x+e^x^2)求dy/dxy=ln(x+e^x^2)dy/dx=y''=[1/(x+e^x^2)]*(

已知y=ln(x+e^x^2) 求dy/dx
已知y=ln(x+e^x^2) 求dy/dx

已知y=ln(x+e^x^2) 求dy/dx
y=ln(x+e^x^2) dy/dx =y'=[1/(x+e^x^2)]*(1+2xe^x^2)

dy/dx =(1/(x+x+e^x^2))*(1+2xe^x^2)