求极限lim(1/n)*[(sin(pi/n)+sin(2pi/n)+.+sin(n*pi/n)] n->无穷

求极限lim(1/n)*[(sin(pi/n)+sin(2pi/n)+.+sin(n*pi/n)] n->无穷 求极限 lim sin pi(n^2+1)^(1/2) 求极限 lim sin pi*(n^2+1)^(1/2) 求极限 lim Sin[pi*√(n^2+1)] n→∞ 求极限lim(n*sin(pi/n)) (n->无穷大)请写出解题过程谢谢 求极限：lim((2n∧2-3n+1)/n+1)×sin n趋于无穷 求极限lim n→∞ 根号n乘以sin n 除以n+1 大一求极限lim(n/(n2+1)+n/(n2+2^2)+……+n/(n2+n2))pi/4 求极限,lim n趋向无穷大,√n*sin(1/√n)=1 求极限lim(n→无穷) (三次根号下n^2)*sin /(n+1) 极限 lim(x-->无穷)(1/n sin(n)+1/n sin(1/n)+nsin(1/n))求极限lim(x-->无穷)(1/n sin(n)+1/n sin(1/n)+nsin(1/n)) 求极限 lim x-无穷 sin(n+1)/(n+a) 正无穷 lim(n->无穷) （tan(pi/4 + 1/n)） ^n的极限 为什么是 e^2 高数求极限n趋于无穷大时,lim (1/n - sin(1/n))/ (1/n^2),lim (1/n - sin(1/n))/ (1/n^3)这一式子呢求极限n趋于无穷大时,lim (1/n - sin(1/n))/ (1/n^2),lim (1/n - sin(1/n))/ (1/n^3)这一式子呢? 求下列极限.lim(n趋向于无穷大)(2x次方)*(sin*1/2x次方) 求极限lim 2/(3^n-1) 利用无穷小的性质求极限lim(x→+∞)[(n^2+1)/n^3]sin(n!)= 求极限 lim(n->∞) (n!/n^e)^1/n