求极限lim(n*sin(pi/n)) (n->无穷大)请写出解题过程谢谢

求极限lim(1/n)*[(sin(pi/n)+sin(2pi/n)+.+sin(n*pi/n)] n->无穷 求极限 lim sin pi(n^2+1)^(1/2) 求极限 lim sin pi*(n^2+1)^(1/2) 求极限lim(n*sin(pi/n)) (n->无穷大)请写出解题过程谢谢 求极限 lim Sin[pi*√(n^2+1)] n→∞ 求极限：lim((2n∧2-3n+1)/n+1)×sin n趋于无穷 求极限lim n→∞ 根号n乘以sin n 除以n+1 极限 lim(x-->无穷)(1/n sin(n)+1/n sin(1/n)+nsin(1/n))求极限lim(x-->无穷)(1/n sin(n)+1/n sin(1/n)+nsin(1/n)) 求下列极限:lim（n×sinπ/n)lim<n→∞>（nsinπ/n) n趋向无穷时,求 nsin(pi/n)的极限可以问一下为甚麼sin(pi/n)可以变pi/n跟外面直接约吗? 求极限 x→π lim sin mx/sin nx (m,n∈N) 大一求极限lim(n/(n2+1)+n/(n2+2^2)+……+n/(n2+n2))pi/4 求极限lim(n→无穷) (三次根号下n^2)*sin /(n+1) 求极限,lim n趋向无穷大,√n*sin(1/√n)=1 lim 2^n *sin(x/2^n)n→∞求极限 求极限lim(n->∞)2^n*sin(π/2^n) 求极限.lim n→∞ 2^n sin (π/2^n) 求极限lim(n→∞) sin²[π√(n²+n)]怎么解