(x-y-2)2+x+y+1的值
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(x-y-2)2+x+y+1的值(x-y-2)2+x+y+1的值(x-y-2)2+x+y+1的值(x-y-2)^2+x+y+1的绝对值=0所以x-y-2=0x+y+1=0所以x-y=2x+y=-1所以
(x-y-2)2+x+y+1的值
(x-y-2)2+x+y+1的值
(x-y-2)2+x+y+1的值
(x-y-2)^2+x+y+1的绝对值=0
所以
x-y-2=0
x+y+1=0
所以x-y=2
x+y=-1
所以
(x-y)^2+3(x+y)^3-2(x-y)^2-(x+y)^3
=-(x-y)^2+2(x+y)^3
=-4+(-2)
=-6
这样可以么?
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