化简 √2/4sin(π/4-x)+√6/4cos(π/4-x)

已知sin[a-b]cos a-cos[b-a]sin a=3/5,b是第三象限角,求sin[b+5π/4]的值第一题1/2cos x-√3/2sin x第二题√3sin x+cos x第三题√2[sin x-cos x]第四题√2cos x-√6sin x 化简 √2/4sin(π/4-x)+√6/4cos(π/4-x) 化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x) √2sin(x-π／4）+√6cos（x-π／4）化简 化简√2sin(π/4-x)+√6cos(π/4-x) 化简sin^4x-sin^2x+cos^2x 化简:sin^4 x-sin^2 x+cos^2 x 化简f(x)=(1-√2*cos(2x-π/4))/sin(π/2-x) 化简f(x)=(1+√2*cos(2x-π/4))/sin(π/2-x) 化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x 函数f(x)=sin(2x-π/4)-2√2sin^2x求最小正周期函数f(x)=sin(2x-π/4)-2√2sin^2x的最小正周期 根号2sin(x+π/4)化简 已知sin(x+π/6)=1/4,求sin(5π/6-x)+sin^2(π/3-x) 2sin(x+π/4)sin(x-π/4)=? 2sinωx+2cosωx怎样化为2√2×sin（ωx+π/4) 函数f(x)=sin(2x-π/4)-2√2sin²x的最小正周期 f(x)=sin(2x-π/4)-2√2sin²x的最小正周期是 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1