bn=2^(2n-1)-2n,求{bn}的前n项和Tn

数列b(n+1)=bn+ 2^n.求bn. bn+1=bn+2n-1 bn=-1 求bn通项 已知数列{ bn } 满足2b(n+1)= bn + 1/bn ,且bn>1,求{bn}通项公式 数列{bn}中,b1=1,b(n+1)^2-bn^2=2,求bn 数列b1=3,bn+1=3bn+2n,求bn通项. 高一数学题；已知bn-bn-1=2n-6 求bn的通项公试. 数列bn的通项公式为bn=2/n*(n-1),求bn的前n项和. bn=2^(2n-1)-2n,求{bn}的前n项和Tn bn=(n+1)2n,求数列{bn/1}的前n项和Tn 数列{bn}满足bn=(2n-1)/3^n,求前n项和,Tn 等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn bn=1/(2n-1)(2n+1),数列bn的前n项和为Bn,求证,Bn 已知数列{bn}满足b1=-1,b(n+1)=bn+(2n-1),求bn 正数列{bn}前n项和Sn·且Sn=1/2(bn+n/bn)求Sn 数列bn的前n项和为Tn,6Tn=(3n+1)bn+2,求bn 已知数列bn满足bn=b^2n,其前n项和为Tn,求(1-bn)/Tn 若数列bn中,b1=3,bn+1=（2n-1）bn/2n+1 (n≥1),求bn 计算等差数列{an}{bn}的前n项和分别为An.Bn,且An/Bn=2n/(n+1)求limn→∞(an/bn)