急求!lim(x-arctan(cosx))/(x+arctan(cosx)),x趋向于无穷大
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急求!lim(x-arctan(cosx))/(x+arctan(cosx)),x趋向于无穷大急求!lim(x-arctan(cosx))/(x+arctan(cosx)),x趋向于无穷大急求!lim
急求!lim(x-arctan(cosx))/(x+arctan(cosx)),x趋向于无穷大
急求!lim(x-arctan(cosx))/(x+arctan(cosx)),x趋向于无穷大
急求!lim(x-arctan(cosx))/(x+arctan(cosx)),x趋向于无穷大
因为-π/2<arctanx<π/2
所以arctan(cosx)是有界函数
故lim【x→+∞】[x-arctan(cosx)]/[x+arctan(cosx)]
=lim【x→+∞】[1-arctan(cosx)/x]/[1+arctan(cox)/x]
=(1-0)/(1+0)
=1
答案:1
急求!lim(x-arctan(cosx))/(x+arctan(cosx)),x趋向于无穷大
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