若limx~∞[ax^3+(b-1)x^2+2/x^2+1]=1,求a,b的值
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若limx~∞[ax^3+(b-1)x^2+2/x^2+1]=1,求a,b的值若limx~∞[ax^3+(b-1)x^2+2/x^2+1]=1,求a,b的值若limx~∞[ax^3+(b-1)x^2+
若limx~∞[ax^3+(b-1)x^2+2/x^2+1]=1,求a,b的值
若limx~∞[ax^3+(b-1)x^2+2/x^2+1]=1,求a,b的值
若limx~∞[ax^3+(b-1)x^2+2/x^2+1]=1,求a,b的值
limx~∞[ax^3+(b-1)x^2+2/x^2+1]=limx~∞ax+b-1=1 ﹙分子分母的低阶直接略去﹚
∴a=0 b=2
lim[ax^3+(b-1)x^2+2/x^2+1]=1
x→∞
则 a=0 b-1=1
故 a=0,b=2
经过我详细的计算 a=0 ,b=1
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