1/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)=0
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1/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)=01/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)=01/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)=0是
1/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)=0
1/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)=0
1/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)=0
是不是写错了?应该是解方程1/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)吧
两边通分 2/[(x+1)*(x+3)]=2/[(x+5)*(x+7)]
(x+1)*(x+3)=(x+5)*(x+7)
x^2+4*x+3=x^2+12*x+35
8*x=-32
x=-4
1/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)
x=-4
1/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)=0
方程(组)无解
不可能有解吧
无解
你确定题目没写错?
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