u=ln(xy+z)求du=
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/11 05:28:40
u=ln(xy+z)求du=u=ln(xy+z)求du=u=ln(xy+z)求du=u=ln(xy+z)du=d[ln(xy+z)]/dx*dx+d[ln(xy+z)]/dy*dy+d[ln(xy+z
u=ln(xy+z)求du=
u=ln(xy+z)求du=
u=ln(xy+z)求du=
u=ln(xy+z)
du=d[ln(xy+z)]/dx*dx+d[ln(xy+z)]/dy*dy+d[ln(xy+z)]/dz*dz
=y/(xy+z)*dx+x/(xy+z)*dy+1/(xy+z)*dz
=(ydx+xdy+dz)/(xy+z)
u=ln(xy+z)求du=
帮帮忙拜托啦u=ln(x^y乘y^z乘z^y)求du
求函数u=ln(2x+3y+4z^2)的全微分du
设u=ln√(x^2+y^2+z^2) 求du
设u=xsin2y+y^2z+e^(xy),求du打错题目……设u=xsin2y+y^2z+e^(yz),求du
u=xy^2+arctan(xy) 求du
设z=uv,u=e^(x+y),v=ln(xy)求dy
设z=ln(eu+v),v=xy,u=x2-y2,求dz/dx,dz/dy.
设u=f(x,y,z)有连续偏导数,y=y(x)和z=z(x)分别由方程e^xy-y=0和e^z-xz=0所确定求du/dx,求详解,答案是du/dx=f'x+y2/1-xy*f'y+z/xz-x*f'z
求z=ln(xx-xy)的定义域.
求z={ln(xy)}^0.5的偏导数,
求 z=根号下ln(xy) 的偏函数
求z=根号ln(xy)的偏导
z=ln(xy+z),求Z对x求微分怎么求
设u=cosh(xy)+cos(xy),则du=
设u=f(x,y,z)有连续偏导数,y=y(x)和z=z(x)分别由方程e^xy-y=0和e^z-xz=0所确定,求du/dx
u=f(x,y,z),y=y(x),z=z(x)分别由e^xy-y=0和e^z-xz=0确定,求du/dx
函数u(x,y,z)=4xy^3+5x^2y^6+xz的全微分du