y"=e^2y y|x=0 =0 y'|x=0 =0 求微分方程

微积分方程求解e^x + (e^x cot y + 2y csc y)y' = 0 f(x,y)=e^-y,0 常微分方程的通解dy/dx=(x-y+1)/(x+y-3)y^4=2y^n+y=0y''+6y'+9y=e^(-3x)y''+y'-2y=4e^(2x) (y/x)y'+e^y=0的通解, 求微分方程通解 (y/x)y'+e^y=0 y''(e^x+1)+y'=0 y''=(y')^3+y' 自学高数中,感激不尽 验证Y=e^X sinx满足关系式y''-2y'+2y=0jijiji y^2*cosx+e^y=0 ,y是x的函数,求y‘ [e^(x+y)-e^x]dx+[e^(x+y)-e^y]dy=0求通解 y'-2y=(e^x)-x 有关概率论方差的问题D(X+Y)=D(X)+D(Y)+2E{(X-E(X))(Y-E(Y))} 为什么x y 独立时2E{(X-E(X))(Y-E(Y))} =0?求证明, 以y=C1 e^x+C2 x e^(-x)为通解的微分方程y''-2y'+y=0 设e^Y + XY =e 确定函数y=y（x）求Y''(0). 1、y’=(xy+y)/(x+xy),y(1)=1 2、(y/x)y’+e^y=0,y(1)=0 求解微分方程, e^y+ln(xy)-e^(-x)=0,求y' 求y''+2y'+y=e^-x/x的通解y''+2y'+y=（e^-x）/x 已知y=y(x)由方程cos(x+y)+e^(x-y)=2 y' y'|(x,y)=(0,0)已知y=y(x)由方程cos(x+y)+e^(x-y)=2所确定,求y' ,y'|(x,y)=(0,0) y''-3y'+2y=2e^x