x'2+2x+y'2-8y+17=0,求x'y的值
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x''2+2x+y''2-8y+17=0,求x''y的值x''2+2x+y''2-8y+17=0,求x''y的值x''2+2x+y''2-8y+17=0,求x''y的值即(x²+2x+1)+(y²-
x'2+2x+y'2-8y+17=0,求x'y的值
x'2+2x+y'2-8y+17=0,求x'y的值
x'2+2x+y'2-8y+17=0,求x'y的值
即(x²+2x+1)+(y²-8y+16)=0
(x+1(²+(y-4)²=0
所以x+1=y-4=0
x=-1,y=4
所以x的y次方=1
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