若f(sinx)=2-cos2x,则f(cosx)等于?

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若f(sinx)=2-cos2x,则f(cosx)等于?若f(sinx)=2-cos2x,则f(cosx)等于?若f(sinx)=2-cos2x,则f(cosx)等于?f(cosx)=f[sin(π/

若f(sinx)=2-cos2x,则f(cosx)等于?
若f(sinx)=2-cos2x,则f(cosx)等于?

若f(sinx)=2-cos2x,则f(cosx)等于?
f(cosx)
=f[sin(π/2-x)]
=2-cox[2(π/2-x)]
=2-cos(π-2x)
=2+cos2x

f(sinx)=2-cos2x=2-(1-2sin^2x)
=2sin^2x+1
f(cosx)=2cos^2x+1=cos2x+2

f(cosx)=f(sin(pi/2-x))=2-cos(pi-2x)=2+cos2x
pi是圆周率