极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-1 问lim【sin(x+π)】/x =lim(-sinx)/x 这步怎么出来的?

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/20 13:03:30
极限lim【sin(x+π)】/xx趋向于0就能推出lim【sin(x+π)】/x=lim(-sinx)/x=-1问lim【sin(x+π)】/x=lim(-sinx)/x这步怎么出来的?极限lim【

极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-1 问lim【sin(x+π)】/x =lim(-sinx)/x 这步怎么出来的?
极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-1

问lim【sin(x+π)】/x =lim(-sinx)/x 这步怎么出来的?

极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-1 问lim【sin(x+π)】/x =lim(-sinx)/x 这步怎么出来的?
中学:sin(x+π) = - sinx
高数:lim(x->0) sinx / x = 1