lim x→0 ln(sin(mx))/ln(sin(nx))=?

lim x→0 ln(sin(mx))/ln(sin(nx))=? lim(x趋向0)ln(1+sin x)/x^2 帮忙解决下列极限计算lim（ln Sin x / ln x ) x→0 X趋向于0 lim[sin(ln x)-sin(ln sinx)],x趋近于0+ 求极限：lim x→0 ln[1+sin^2(x)]/[e^(x^2)－1] lim(x→0)[ln(1+x^2)]/[sin(1+x^2)] 求lim(x→0)(sin(ln(1+x)/x-1)/sinx 求下列极限,lim(sin mx)/(sin nx）,x→0烦请给出具体步骤, 求极限 ln x/ ln (sin x),lim x->0 请用洛必达法则求解, lim→0+ lnx ln(1+X) lim(x→0+)[ln(sin5x)]/[ln(sin3x)] 这题咋做 lim x→0 ln(cos5x)/ln(cos2x)要过程 x→0+时 求lim ln(tan3x)/ln(tan2x) 求极限lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0 lim x→0 (x^4*sin(1/x)+（e^(x^4)）-1)/(ln(1+sinx-tanx)) 求解当x趋向0时lim[sin(2^x)ln(x+1)]/(2^x-1) 求极限ln(1+2x)/sin(1+2x),lim x->0求它极限. 求极限lim(x趋向于0)ln(1+x^2)/sin(1+x^2)