若π/12
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若π/12若π/12若π/12π/12sin2x=sin(2x+π/3-π/3)=sin（2x+π/3）cosπ/3-cos（2x+π/3）sinπ/3=12/13*1/2+5/13*√3/2=(12
若π/12 若π/12
若π/12
π/12
=sin（2x+π/3）cosπ/3-cos（2x+π/3）sinπ/3
=12/13*1/2+5/13*√3/2
=(12+5√3)/26
若π/12
若x=π/12,则cos(2x-π)*cos[2(x-π)]=?
若cos(5π/12＋θ)=1/7,则sin(π/12－θ)
若θ∈[-π/12,π/12],则函数y=cos(θ+π/4)+sin2θ 最小值
若x=π/12,则cos4x-sin4x
若x=π/12,则cos4x-sin4x
若π
若π
若π
若π
若cos(π/4+x)=3/5 17π/12
若cos（π/4+x）=3/5,17/12π
若cos(π/4+x)=3/5,17π/12
若cos(π/4+x)=3/5,17π/12
若cos（α-π/3）=12/13,π/3
若cos(π/4+x)=3/5 17π/12
若sin(π/4-α)=3/5 sin(π/4+β)=12/130
若cos(π/4+x)=3/5 17π/12