复数z=sin(π/6)_icos(π/3)的模是多少啊?

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复数z=sin(π/6)_icos(π/3)的模是多少啊?复数z=sin(π/6)_icos(π/3)的模是多少啊?复数z=sin(π/6)_icos(π/3)的模是多少啊?|z|=根号[(sinπ/

复数z=sin(π/6)_icos(π/3)的模是多少啊?
复数z=sin(π/6)_icos(π/3)的模是多少啊?

复数z=sin(π/6)_icos(π/3)的模是多少啊?
|z|=根号[(sinπ/6)^2+(cosπ/3)^2]
=根号(1/4+1/4)=根号2/2

|z|=根号下[(sinπ/6)^2+(cosπ/3)^2]=根号下(1/4+1/4)=根号2/2