(X+4) log2 =(1/3)^绝对值X的解?X+4真书,2底数

[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙! log2(4^x+4)=x+log2(2^x+1-3)log2(4^x+4)=x+log2[2^(x+1)-3] log2(2^x-1)log2(2^(x+2)-4=3log2(2^x-1)log2(2^(x+2)-4）=3 求解log2(3x)=log2(2x+1) log2(x+1)+log2(x+8)=3的解集是? 解方程log2^(4^x+4)=x+log2^[2^(x+1)-3] 解方程：log2(4^x+4)=x+log2(2^(x+1)-3) 高一数学log2（4^x+4)=x+log2(2^(x+1)-3) 解方程log2(4^x+1)=x+log2(2^(x+3)-6) 谁能帮我解一下：log2(x + 1) = 4 - log2(x + 1)log2(x + 1) = 4 - log2(x + 1) 解方程：log2(x+4)+log2(x-1)=1+log2(x+8) 解方程log2(2x+1)=log2(3x-4) |[log2(x)]^2-3log2(x)+1| log2(x+1)>log2(3-x) log2 (x+1)+log2 x=log6 log2(x)=-1