2∧(1-1/2log2(5))=?

[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 解2log2^(x-5)=log2^(x-1)+1 求值：log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的？ log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 计算：（1）log2 (4^3*8^5);(2)log2 3+log2 6-log2 9 (log2) ^2 - log5 *log20课本上 等于 （log2）^2 +(1+log2)(1-log2) = 1;（log2）^2 +(1+log2)(1-log2) 是怎么来的? log2 SQR(7/48)+log2 12 -1/2log2 42 log2 SQR(7/48)+log2 12 -1/2log2 48 解方程log2(2-x)=log2(x-1)+1 4^1/2（log2^9-log2^5）的值 , 求解log2(3x)=log2(2x+1) |[log2(x)]^2-3log2(x)+1| (log2)2+log2*log50+1g25值 log2 1+ log2 2+ … + log2 n >= ⌊n/2」log2 (n/2) 求证明,2是底 lg(1/4)-lg2(5) 2log5(10)+log5(0.25) 2log2(25)-3log2(64) log2(log2(16) ) log2底根号5/56+log2(14)-1/2log2(35)答案是-1/2 根号下{[log2 （5)]^2-4log2(5)+4}+log2(1/5) 计算 根号下[(log2 5)^2-4log2 5+4]+log2 1/5