求极限···lim ln(sinx/x) x趋近0

求极限···lim ln(sinx/x) x趋近0 求极限:lim(x->0) ln(sinx/x)/(x*x) 1、lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx2、lim (2+3x)^2·sinx-4sinx/1-cos(x/3) x均趋近于0,求此二题极限 求极限lim(x->0) [ln(1+x^2)-ln(1+sinx^2)]/xsinx^3 求极限：lim{[x-ln(1+tanx)]/sinx*sinx},x趋于0, 求帮忙 用洛必达法则求极限：lim（x→0)(ln sin3x)/(ln sinx) 求极限(1). lim(x-o) ln(sinx/x) (2). lim(n->∞){x[ln(x+a)-lnx]} 求极限lim(t→x)(sint/sinx)^【x/（sint-sinx)】,这道题“e^ln(sint/sinx)^[x/(sint-sinx)]”, 求极限lim(x→0)[2sinx+x^2(sin1/x)]/ln(1+x) 求极限lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0 求极限,lim(x->0) (e^x-e^sinx ) / [ (tanx )^2 * ln(1+2x)] 利用洛必达法则求下列极限:lim(x→0)ln(1+x)-x/sinx. 求极限： Lim x→0(1/sinx - 1/x)详解··· 求lim x→0 1-cos2x/x·sinx极限 求极限lim(x→0)][ln(1+2x^2)+n sinx]/(1-cosx) 求极限lim(x→π/2) ln(sinx)/[(π-2x)^2]怎么计算? lim ln(sinx/x)的极限.x趋向于0 求极限lim(1-cos(1-cosX))/(sinx^2*ln(1+x^2))有图.