求证lim(n→∞)[2^(1/n)]=1分析和证明都要.

求证lim(n→∞)[2^(1/n)]=1分析和证明都要. 求证lim（n→∞）n/（2^n）=0没有学到洛毕塔法则~ 求证lim（1+1/n+1/n2）n =e ( n→∞)式中的2是平方! 求证lim n/(n!)^(1/n)=e 求极限 lim(n→∞) tan^n (π/4 + 2/n) lim(n→∞)tan^n(π/4+2/n) =lim(n→∞)[(tan(π/4)+tan(2/n))/(1-tan(π/4)tan(2/n))]^n =lim(n→∞)[(1+tan(2/n))/(1-tan(2/n))]^n =lim(n→∞)(1+tan(2/n))^n/(1-tan(2/n))^n (1) 因为 lim(n→∞)(1+tan(2/n) 用数列极限证明lim(n→∞)(n^-2)/(n^+n+1)=1中证明如下:lim(n→∞)3n+1/5n-4 极限 lim(n→∞)[(n!)^2/(2n)!]= lim(n→∞) 2^n/n!=0 求lim n→∞ (1+2/n)^n+3 lim(n→∞)[1-(2n/n+3)] lim(n→∞)(2n-1/n+3) lim n→∞ n^(3/2)* (n+1)^(1/2)* (1-cos(π/n))=? lim(n→∞)(2n-1/2n+1)^n= 大一高数~ lim n→∞ n/√(2n+1)(n+1)= 证明lim(n→∞){n-根号下n^2-n}=1/2 lim n->∞{2/((1+ 1/n )^n)}=? lim(n→∞)(根号n+2-根号n)*根号n-1=? n→∞ lim(n+3/n+1)^2n=