求dy/dx=1-x+y^2-xy^2的通解
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求dy/dx=1-x+y^2-xy^2的通解求dy/dx=1-x+y^2-xy^2的通解求dy/dx=1-x+y^2-xy^2的通解dy/dx=(1-x)+y^2(1-x),dy/dx=(1-x)(1
求dy/dx=1-x+y^2-xy^2的通解
求dy/dx=1-x+y^2-xy^2的通解
求dy/dx=1-x+y^2-xy^2的通解
dy/dx=(1-x)+y^2(1-x),
dy/dx=(1-x)(1+y^2),
dy/(1+y^2)=(1-x)dx,
∫ dy/(1+y^2)=∫(1-x)dx,
∴微分方程通解为:arctany=x-x^2/2+C,
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