验证(n^2-n+2)/(3n^2+2n-4)在n趋向无穷大时极限为1/3.
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验证(n^2-n+2)/(3n^2+2n-4)在n趋向无穷大时极限为1/3.验证(n^2-n+2)/(3n^2+2n-4)在n趋向无穷大时极限为1/3.验证(n^2-n+2)/(3n^2+2n-4)在
验证(n^2-n+2)/(3n^2+2n-4)在n趋向无穷大时极限为1/3.
验证(n^2-n+2)/(3n^2+2n-4)在n趋向无穷大时极限为1/3.
验证(n^2-n+2)/(3n^2+2n-4)在n趋向无穷大时极限为1/3.
lim(n^2-n+2)/(3n^2+2n-4) n趋向无穷大
=lim(2n-1)/(6n+2)
=lim2n/6n
=1/3
分子，分母同除以n^2,在利用极限运算的四则运算法则不就完事了吗，还用罗比达法则干吗？
证明不等式：(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
验证(n^2-n+2)/(3n^2+2n-4)在n趋向无穷大时极限为1/3.
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