求：Lim sinx/ln(1+x)x->0本人很菜,

求极限:lim(x->0) ln(sinx/x)/(x*x) 求极限(1). lim(x-o) ln(sinx/x) (2). lim(n->∞){x[ln(x+a)-lnx]} 求极限lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0 求极限lim(x->0) [ln(1+x^2)-ln(1+sinx^2)]/xsinx^3 求极限：lim{[x-ln(1+tanx)]/sinx*sinx},x趋于0, 求帮忙 求极限lim(x→0)[2sinx+x^2(sin1/x)]/ln(1+x) 求lim(x→0)ln[1+e^x(sinx)^2]/√(1+x^2)-1 x 趋向于0 求lim(cos1/x+2/sinx-1/ln(1+x)) lim(ln(1+f/sinx))/2^x-1＝3求limf(x)/x² 求lim(x→0)(sin(ln(1+x)/x-1)/sinx 求极限,lim(x->0) (e^x-e^sinx ) / [ (tanx )^2 * ln(1+2x)] 利用洛必达法则求下列极限:lim(x→0)ln(1+x)-x/sinx. 怎么计算lim(x->0+)x^(1/2)*ln(sinx)? lim x->0 ln(1-sinx)/x 的值是 lim x->0 ln(1-sinx)/x 的值是 lim(x趋近0)ln(x/sinx) 求极限lim(x→0)][ln(1+2x^2)+n sinx]/(1-cosx) 求lim(tanx-sinx)/ln(1+x³)x→0