tanx=6,1/2sin^2x+1/3cos^2x=?

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tanx=6,1/2sin^2x+1/3cos^2x=?tanx=6,1/2sin^2x+1/3cos^2x=?tanx=6,1/2sin^2x+1/3cos^2x=?1/2sin^2x+1/3cos

tanx=6,1/2sin^2x+1/3cos^2x=?
tanx=6,1/2sin^2x+1/3cos^2x=?

tanx=6,1/2sin^2x+1/3cos^2x=?
1/2sin^2x+1/3cos^2x
=1/3(sin^2x+cos^2x)+1/6sin^2x
=1/3+1/6sin^2x
因为tanx=6=sinx/cosx
所以两边平方得sin^2x=36cos^2x
又sin^2x+cos^2x=1
所以sin^2x=36/37
所以1/3+1/6sin^2x
=1/3+(1/6)*(36/37)
=37/111+18/111
=55/111
懂了么
有什么不懂的可以问我

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