lim函数[ln(1/x)]^x(x趋向于0+)的值
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lim函数[ln(1/x)]^x(x趋向于0+)的值lim函数[ln(1/x)]^x(x趋向于0+)的值lim函数[ln(1/x)]^x(x趋向于0+)的值y=[ln(1/x)]^x两边同时取自然对数
lim函数[ln(1/x)]^x(x趋向于0+)的值
lim函数[ln(1/x)]^x(x趋向于0+)的值
lim函数[ln(1/x)]^x(x趋向于0+)的值
y=[ln(1/x)]^x
两边同时取自然对数得:
lny=xln(1/x)
那么lim【x→+0】lny
=lim【x→+0】xln(1/x)
=lim【x→+0】ln(1/x)/(1/x)
=lim【x→+0】x·(1/x) '/(1/x) '
=0
所以lim【x→+0】[ln(1/x)]^x=1
答案:1
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