lim(x趋向于无穷大时)x^2[1-cos(1/x)]
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/24 05:13:33
lim(x趋向于无穷大时)x^2[1-cos(1/x)]lim(x趋向于无穷大时)x^2[1-cos(1/x)]lim(x趋向于无穷大时)x^2[1-cos(1/x)]limx->∞x²[1
lim(x趋向于无穷大时)x^2[1-cos(1/x)]
lim(x趋向于无穷大时)x^2[1-cos(1/x)]
lim(x趋向于无穷大时)x^2[1-cos(1/x)]
lim x->∞ x²[1 - cos(1/x)]
= lim x->∞ [1 - cos(1/x)] / (1/x²) (分子, 分母同时趋向於0, 可利用洛必达法则)
= lim x->∞ {0 - [-sin(1/x)] * [-x^(-2)]} / [-2x^(-3)]
= lim x->∞ [sin(1/x)] / (2/x) (分子, 分母同时趋向於0, 可利用洛必达法则)
= lim x->∞ [cos(1/x) * (1/x)'] / (2/x)'
= lim x->∞ [cos(1/x)] / 2
= cos(0) / 2
= 1/2
lim(x趋向于无穷大时)e^(1/x)
lim(x趋向于无穷大时)[x^2/(x^2-1)]^x
lim(x趋向于无穷大时)cos{ln[1+(2x-1)/x^2]}
lim(x趋向于正无穷大时)(1-1/X)^(x^1/2)
lim(x趋向于无穷大时)x^2[1-cos(1/x)]
求lim (Inx)^1/x (X趋向于无穷大 )
lim趋向于无穷大时(e的x/2次方)-1的极限
1.lim x趋向于无穷大sinx/x+1=? 2.lim x趋向于无穷大(1+2/x)^x+3=?
LIM(INX)/X趋向于无穷大
lim(x趋向于正无穷大时)[√(x^2+2x)-√(x-1)]/x
求极限lim[x-x^2ln(1+1/x)] 其中x趋向于正无穷大
求极限lim(根号x^2-x+1减去x),x趋向于正无穷大
当x趋向于无穷大时,lim(2x+3/2x+1)^(x+1)=怎么计算啊
lim【(arctan x)*(cos(1/x))】,当x趋向于无穷大时,求极限
当x趋向于无穷大时,lim[(x+sinx)/x]为什么等于1?
lim(x趋向于正无穷大时)[sin√(x+1)-sin√x]
x趋向于无穷大时lim(1+k/x)^x 如何用洛必达法则求解
x趋向于无穷大时,lim(2x-sinx)/(x+cosx)的极限