lim(x趋向于无穷大时)cos{ln[1+(2x-1)/x^2]}
来源:学生作业帮助网 编辑:六六作业网 时间:2025/02/03 01:36:29
lim(x趋向于无穷大时)cos{ln[1+(2x-1)/x^2]}lim(x趋向于无穷大时)cos{ln[1+(2x-1)/x^2]}lim(x趋向于无穷大时)cos{ln[1+(2x-1)/x^2
lim(x趋向于无穷大时)cos{ln[1+(2x-1)/x^2]}
lim(x趋向于无穷大时)cos{ln[1+(2x-1)/x^2]}
lim(x趋向于无穷大时)cos{ln[1+(2x-1)/x^2]}
x趋向于无穷大时,(2x-1)/x^2=0
所以原式=cos[ln(1+0)]=cos0=1
lim(x趋向于无穷大时)cos{ln[1+(2x-1)/x^2]}
lim cos x/x 的极限值[x趋向于无穷大]
lim【(arctan x)*(cos(1/x))】,当x趋向于无穷大时,求极限
lim(x趋向于无穷大时)x^2[1-cos(1/x)]
lim[cos ln(1+x)-cos ln(x)]x趋向于正无穷
求极限:lim[1/x+ln(1+e^x)]当x趋向于负无穷大时极限,
求极限lim[x-x^2ln(1+1/x)] 其中x趋向于正无穷大
求极限 lim(x趋向于无穷大) x{ln(2+1/x)-ln2} 要详解
lim(x趋向于无穷大时)e^(1/x)
LIM(INX)/X趋向于无穷大
求极限lim(x趋向无穷大)ln(1+x)/x
求极限 lim(x趋向于无穷大) x{ln(2+1/x)-ln2} 要详解求极限 lim(x趋向于无穷大) x{ln(2+1/x)-ln2} 要详解
求极限 lim x趋向于无穷大ln(x/根号下x平方-1lim x趋向于无穷大ln(x/根号下x平方-1)怎么算,要过程谢谢!
x趋向于0+,lim(ln(tan4x)/ln(tanx))
n趋向于无穷大,lim n[ln(n+2)-ln(n+1)],
一高数题lim(x趋向于无穷大)arctan(x/3)是多少
求lim (Inx)^1/x (X趋向于无穷大 )
lim(x趋向于无穷大时)[x^2/(x^2-1)]^x