lim(x→0)[(1+xsinx)^1/2-1]/(sinx)^2=
来源:学生作业帮助网 编辑:六六作业网 时间:2025/02/01 14:52:01
lim(x→0)[(1+xsinx)^1/2-1]/(sinx)^2=lim(x→0)[(1+xsinx)^1/2-1]/(sinx)^2=lim(x→0)[(1+xsinx)^1/2-1]/(sin
lim(x→0)[(1+xsinx)^1/2-1]/(sinx)^2=
lim(x→0)[(1+xsinx)^1/2-1]/(sinx)^2=
lim(x→0)[(1+xsinx)^1/2-1]/(sinx)^2=
lim(x→0) [√(1 + xsinx) - 1]/sin²x
= lim(x→0) [√(1 + xsinx) - 1]/x²、sinx x
= lim(x→0) [√(1 + xsinx) - 1]/x² * [√(1 + xsinx) + 1]/[√(1 + xsinx) + 1]
= lim(x→0) [(1 + xsinx) - 1]/[x²(√(1 + xsinx) + 1)]
= lim(x→0) xsinx/[x²(√(1 + xsinx)) + 1]、sinx x
= lim(x→0) x²/[x²(√(1 + xsinx)) + 1]
= lim(x→0) 1/[√(1 + xsinx) + 1]
= 1/[√(1 + 0) + 1]
= 1/2
lim(x→0)(1-cos4x)/xsinx
lim(x→0)(1-cos2x)/xsinx
lim(x→0) sinx-x(x+1)/xsinx
求极限lim x→0 (1/xsinx+xsin1/x)
lim(x趋向0) 1-cos2x/xsinx
lim(x->0)(2xsinx)/(secx-1)
求极限Lim(x→0)1/xsinx-1/xtanx
求下列极限lim(x→0)(1-cosx)/xsinx
lim(x→0)(1-cosx)/(xsinx)=?
2.5计算极限lim(x→0) (1-cos2x)/xsinx
lim(x→0) xsinx
lim (1/(xsinx)-1/x^2)x~0
:lim(xsin1/x+1/xsinx)x趋于0
lim(x~无穷)xsin1/x-1/xsinx
求lim(x→∞)1-cos2x/xsinx
lim((1-cos2x)/(xsinx)) 当X-->0时的极限
1-√cosx/xsinx 求Lim X趋向于0
lim(x趋向0)(1-cos2x)/xsinx怎么解?